RDvDiDR2500 R1500 Vs6 VZTh iDvDVThVDQRDvDiDR2500 R1Vs6 ViDZThRDvDVTh/ (ZTh + RD)= 0.004VThR1 R2 R1 R2 R2 ZTh VTh a-bvD [V]VTh iD [mA]vDVDQIDQ (9)(11)iDVTh /ZThIDQQ09ab60ababQ0yQiD [mA]3vD [V]43vD= 0.75 ViD= 3mA (9)(11)a-b12 mA/V0.7525272628500 500 (9)(11)1 / 750500 a-b0.51.01 / (ZTh + RD)=
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